Question

What may be the possible code for 'disk only made' in the given code language?

• A. $23\#D,\;36\%E,\;29^{}A$
• B. $36\%E,\;45@K,\;76^{}Y$
• C. $45@K,\;23\#D,\;45@A$
• D. $45@I,\;67\#T,\;21^{}K$
• E.

Hint:

In multi-word coding questions, ensure that you correctly match all of the last letters in the code. The order might not matter, but the presence of the correct letters is crucial.

Answer 1

The Correct Option is B

- The word disk ends with the letter k, so the code should end with K. - The word only ends with the letter y, so the code should end with Y. - The word made ends with the letter e, so the code should end with E. Hence, the code must contain the letters K, Y, and E at the end in some order. Option (b) is the only one that satisfies this condition: it ends with $E$, $K$, and $Y$ in some order. 

Answer 2

Each word's code ends in a capital letter matching its own last letter. "disk" ends in k, so one code must end in K; "only" ends in y, so one code must end in Y; "made" ends in e, so one code must end in E. The correct option must contain all three of these endings together.

1. Option A: 23#D, 36%E, 29^A ends in D, E and A — it has E but is missing both K and Y, so it fails.
2. Option B: 36%E, 45@K, 76^Y ends in E, K and Y — exactly the three endings required, so it fits.
3. Option C: 45@K, 23#D, 45@A ends in K, D and A — it has K but is missing Y and E, so it fails.
4. Option D: 45@I, 67#T, 21^K ends in I, T and K — it has K but is missing Y and E, so it fails.

Only option B carries the required K, Y and E endings for "disk", "only" and "made".

Hence, the correct answer is 36%E, 45@K, 76^Y.