We have
\(⇒ \frac{(M + S)}{2 }= 140\)
\(⇒ S + E = 140\)
We cannot find values of his marks obtained from the above two equations and from (i) only weights of the subjects are given. To find the weighted average we need both weights and values of the subjects. So from (i) and (ii) we cannot solve the question. Hence, option D is the correct answer.
What is the total mark in the examination?
Statements:
I. A student secures 36% but fails by 6 marks.
II. The pass mark is 60.