Question:

What is the total number of electrons present in completely filled 3s, 3p, and 3d subshell having same value of magnetic quantum number?

Show Hint

Find the magnetic quantum number value that is present in all three subshells, then count the electrons in those orbitals.
Updated On: Nov 12, 2026
  • \(18\)
  • \(9\)
  • \(6\)
  • \(3\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
For a subshell with azimuthal quantum number \(l\), the magnetic quantum number \(m_l\) takes values from \(-l\) to \(+l\).

Step 2: Allowed values
3s: \(m_l=0\).
3p: \(m_l=-1,0,+1\).
3d: \(m_l=-2,-1,0,+1,+2\).
The only value common to all three is \(m_l=0\).

Step 3: Calculation
There is one orbital with \(m_l=0\) in each of 3s, 3p and 3d, so 3 orbitals in all. Each filled orbital holds 2 electrons, so \(3\times 2=6\) electrons.

Final Answer:
Six electrons share the same magnetic quantum number, which is option (C). \[ \boxed{\text{(C) }6} \]
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