Question:

What is the smallest perfect \(F_2\) population size when four genes are segregating?

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For \(n\) segregating genes, smallest perfect \(F_2\) population size is \(4^n\).
Updated On: May 18, 2026
  • \(64\)
  • \(1024\)
  • \(256\)
  • \(16\)
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The Correct Option is C

Solution and Explanation

Concept:
For \(n\) segregating genes, the smallest perfect \(F_2\) population size is generally calculated as: \[ 4^n \]

Step 1: Identify the number of segregating genes.
\[ n=4 \]

Step 2: Apply the formula.
\[ \text{Smallest perfect }F_2\text{ population size}=4^n \] \[ =4^4 \]

Step 3: Calculate the value.
\[ 4^4=4\times4\times4\times4 \] \[ =256 \] \[ \therefore \text{Correct Answer is (C)} \]
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