What is the ratio of the production of Pulses to that of Wheat over the six years ?


Step 1: Pulses production over years 2011 = 150, 2012 = 50, 2013 = 200, 2014 = 150, 2015 = 250, 2016 = 350.
Total Pulses = \( 1150 \).
Step 2: Wheat production over years 2011 = 250, 2012 = 150, 2013 = 400, 2014 = 100, 2015 = 150, 2016 = 300.
Total Wheat = \( 1350 \).
Step 3: Ratio Pulses : Wheat = \( 1150 : 1350 = 115 : 135 = 23 : 27 \). \[ \boxed{23 : 27} \] So the correct option is (d)
Instead of dividing by 10 and then by 5 in two steps, the ratio can be reduced in one step by finding the greatest common divisor through prime factorisation.
Totals over the six years. Pulses: \(150+50+200+150+250+350=1150\). Wheat: \(250+150+400+100+150+300=1350\).
Reducing via prime factors. \(1150=2\times5^2\times23\) and \(1350=2\times3^3\times5^2\). The common factors are \(2\times5^2=50\). Dividing both by \(50\): \[ \frac{1150}{50}=23,\qquad \frac{1350}{50}=27. \] So the ratio is \(23:27\).
Factoring both totals shows their greatest common divisor directly, without needing an intermediate simplification step.
So the correct answer is 23:27.
What is the difference between the average runs of top two openers in terms of \(\textit{highest runs}\), if matches having 0's were ignored?

If matches having zero runs and the one with highest runs is ignored, what will be the average runs for opener C?

By how much does the difference between the two highest total runs differ from the difference between the two lowest total runs?

Which of the given pairs of openers have ratio \(5:2\) in their highest runs?

If the human body can withstand a maximum of 9720 units of IR rays when exposed to the sun continuously, then what is the maximum time in minutes that any person could stand in the sun without crossing the threshold limit of IR rays?
