Question:

What is the oxidation state of Phosphorus in \( H_3PO_4 \)?

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To find oxidation states in neutral molecules, remember:
Sum of oxidation numbers = 0.
Updated On: Apr 23, 2026
  • +3
  • +5
  • +1
  • +7
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The Correct Option is B

Solution and Explanation

Concept:
The oxidation state (or oxidation number) of an element represents the hypothetical charge it would have if all bonds were completely ionic. In a compound, the sum of oxidation states of all atoms must equal the overall charge of the molecule. For neutral molecules, the total oxidation state equals zero.

Step 1: Assign known oxidation states

In \(H_3PO_4\):
• Hydrogen generally has an oxidation state of \(+1\).
• Oxygen generally has an oxidation state of \(-2\).

Step 2: Let the oxidation state of phosphorus be \(x\)

\[ 3(+1) + x + 4(-2) = 0 \]

Step 3: Solve the equation
\[ 3 + x - 8 = 0 \] \[ x - 5 = 0 \] \[ x = +5 \] Conclusion:
The oxidation state of phosphorus in \(H_3PO_4\) is \(\mathbf{+5}\).
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