Question

What is the oxidation state of sulphur in oil of vitriol?

• A. \(+2\)
• B. \(+6\)
• C. \(-3\)
• D. \(+3\)

Hint:

In sulphuric acid, sulphur always exhibits its highest common oxidation state of \(+6\).

Answer 1

The Correct Option is B

Step 1: Identify oil of vitriol.
Oil of vitriol is the common name of sulphuric acid, whose chemical formula is \(\mathrm{H_2SO_4}\).
Step 2: Assign known oxidation states.
Hydrogen has oxidation state \(+1\) and oxygen has oxidation state \(-2\).
Step 3: Calculate oxidation state of sulphur.
Let the oxidation state of sulphur be \(x\). Then:
\[ 2(+1) + x + 4(-2) = 0 \] \[ x = +6 \]
Step 4: Conclusion.
Therefore, the oxidation state of sulphur in oil of vitriol is \(+6\).