Question:
What is the oxidation state of sulphur in oil of vitriol?
What is the oxidation state of sulphur in oil of vitriol?
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In sulphuric acid, sulphur always exhibits its highest common oxidation state of \(+6\).
Updated On: Mar 28, 2026
- \(+2\)
- \(+6\)
- \(-3\)
- \(+3\)
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The Correct Option is B
Solution and Explanation
Step 1: Identify oil of vitriol.
Oil of vitriol is the common name of sulphuric acid, whose chemical formula is \(\mathrm{H_2SO_4}\).
Step 2: Assign known oxidation states.
Hydrogen has oxidation state \(+1\) and oxygen has oxidation state \(-2\).
Step 3: Calculate oxidation state of sulphur.
Let the oxidation state of sulphur be \(x\). Then:
\[ 2(+1) + x + 4(-2) = 0 \] \[ x = +6 \]
Step 4: Conclusion.
Therefore, the oxidation state of sulphur in oil of vitriol is \(+6\).
Oil of vitriol is the common name of sulphuric acid, whose chemical formula is \(\mathrm{H_2SO_4}\).
Step 2: Assign known oxidation states.
Hydrogen has oxidation state \(+1\) and oxygen has oxidation state \(-2\).
Step 3: Calculate oxidation state of sulphur.
Let the oxidation state of sulphur be \(x\). Then:
\[ 2(+1) + x + 4(-2) = 0 \] \[ x = +6 \]
Step 4: Conclusion.
Therefore, the oxidation state of sulphur in oil of vitriol is \(+6\).
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