What is the oxidation state of Phosphorus in \(H_3PO_4\)?
Show Hint
To find oxidation states quickly, remember common values: Hydrogen \(+1\), Oxygen \(-2\), Alkali metals \(+1\), and the total oxidation number of a neutral compound is always zero.
Concept:
The oxidation state of an element in a compound is calculated by assigning standard oxidation numbers to known atoms and solving for the unknown element.
Rules used:
• Hydrogen generally has oxidation state \(+1\)
• Oxygen generally has oxidation state \(-2\)
• The sum of oxidation states in a neutral compound is zero
Step 1: Assign oxidation states to known elements.
\[
H = +1, \quad O = -2
\]
For \(H_3PO_4\):
\[
3(+1) + x + 4(-2) = 0
\]
where \(x\) is the oxidation state of phosphorus.
Step 2: Solve the equation.
\[
3 + x - 8 = 0
\]
\[
x - 5 = 0
\]
\[
x = +5
\]
Step 3: State the result.
\[
\boxed{+5}
\]