Question:
What is the oxidation number of carbon in K\(_2\)C\(_2\)O\(_4\)?
What is the oxidation number of carbon in K\(_2\)C\(_2\)O\(_4\)?
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Always use the rule: sum of oxidation states in a neutral compound is zero.
Updated On: Feb 11, 2026
- –2
- +3
- 0
- +4
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The Correct Option is B
Solution and Explanation
Step 1: Write oxidation states of known elements.
Potassium (K) has oxidation state +1.
Oxygen (O) has oxidation state –2.
Step 2: Let oxidation state of carbon be \(x\).
\[ 2(+1) + 2x + 4(-2) = 0 \]
Step 3: Solve the equation.
\[ 2 + 2x - 8 = 0 \Rightarrow 2x = 6 \Rightarrow x = +3 \]
Step 4: Conclusion.
The oxidation number of carbon is +3.
Potassium (K) has oxidation state +1.
Oxygen (O) has oxidation state –2.
Step 2: Let oxidation state of carbon be \(x\).
\[ 2(+1) + 2x + 4(-2) = 0 \]
Step 3: Solve the equation.
\[ 2 + 2x - 8 = 0 \Rightarrow 2x = 6 \Rightarrow x = +3 \]
Step 4: Conclusion.
The oxidation number of carbon is +3.
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