Question

What is the number of moles of silver chloride precipitated when excess aqueous silver nitrate is treated with \([\mathrm{Co(NH_3)_4Cl_2]Cl}\)?

• A. 1.0 mole
• B. 3.0 mole
• C. 2.0 mole
• D. 4.0 mole

Hint:

Only ions outside the coordination sphere react with external reagents like AgNO\(_3\).

Answer 1

The Correct Option is A

Step 1: Understanding the complex salt.
The compound \([\mathrm{Co(NH_3)_4Cl_2}]Cl\) contains one chloride ion outside the coordination sphere and two chloride ions inside the coordination sphere.

Step 2: Reaction with silver nitrate.
Only the chloride ion present outside the coordination sphere is free and can react with aqueous silver nitrate to form silver chloride precipitate.

Step 3: Counting precipitable chloride ions.
Since there is only one free \( \mathrm{Cl^-} \) ion, only one mole of AgCl will be formed per mole of the complex.

Step 4: Conclusion.
Therefore, the number of moles of silver chloride precipitated is 1.0 mole.