Question:

What is the number of faraday required to form 1 mol \( \text{H}_2 \) by reduction of \( \text{H}^+ \) ions?

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Check the stoichiometry of electrons in the balanced half-reaction.
Updated On: May 14, 2026
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The Correct Option is B

Solution and Explanation


Step 1: Concept

The number of Faradays required is equal to the number of moles of electrons transferred in the redox reaction.

Step 2: Meaning

Faraday's law relates the chemical change to the quantity of electricity.

Step 3: Analysis

The reduction half-reaction is: \(2H^+ + 2e^- \rightarrow H_{2(g)}\).

Step 4: Conclusion

To produce 1 mole of \(H_2\), 2 moles of electrons are required, which corresponds to 2 Faradays. Final Answer: (B)
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