Question:
What is the gram atomic mass of an element whose mass of one atom is \(3.9853\times 10^{-23}\ \text{g}\)?
What is the gram atomic mass of an element whose mass of one atom is \(3.9853\times 10^{-23}\ \text{g}\)?
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Multiply the mass of one atom by Avogadro's number to get the mass of one mole of atoms.
Updated On: Nov 12, 2026
- \(23\ \text{g}\)
- \(24\ \text{g}\)
- \(27\ \text{g}\)
- \(16\ \text{g}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Gram atomic mass is the mass of one mole of atoms, that is \(6.022\times10^{23}\) atoms.
Step 2: Calculation
Mass of one mole \(= 3.9853\times10^{-23}\ \text{g}\times 6.022\times10^{23} = 24.0\ \text{g}\).
Step 3: Identify
This corresponds to magnesium.
Final Answer:
The gram atomic mass is 24 g. \[ \boxed{\text{(B) }24\ \text{g}} \]
Gram atomic mass is the mass of one mole of atoms, that is \(6.022\times10^{23}\) atoms.
Step 2: Calculation
Mass of one mole \(= 3.9853\times10^{-23}\ \text{g}\times 6.022\times10^{23} = 24.0\ \text{g}\).
Step 3: Identify
This corresponds to magnesium.
Final Answer:
The gram atomic mass is 24 g. \[ \boxed{\text{(B) }24\ \text{g}} \]
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