Concept:
In reverse bias, diode current is approximately equal to drift current (very small and constant).
Step 1: Identify diode condition.
From the circuit, diode is reverse biased.
\[
I = I_{\text{drift}} = 30\,\mu A
\]
Step 2: Voltage drop across resistor.
\[
V_R = IR = (30 \times 10^{-6})(20) = 6 \times 10^{-4}\,V = 0.0006\,V
\]
Step 3: Voltage across diode.
\[
V_D = 6.0 - 0.0006 = 5.9994 = 5.99\,V
\]