Question:

What is the current through the circuit and the potential difference across the diode shown in the figure. The drift current for the diode is \(30\,\mu A\).

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In reverse bias, diode current \(\approx\) constant (drift current), voltage mostly appears across diode.
Updated On: Apr 16, 2026
  • \(30\,\mu A,\, 5.99\,V\)
  • \(30\,\mu A,\, 5\,V\)
  • \(20\,\mu A,\, 6\,V\)
  • \(20\,\mu A,\, 5.99\,V\)
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The Correct Option is A

Solution and Explanation

Concept: In reverse bias, diode current is approximately equal to drift current (very small and constant).

Step 1:
Identify diode condition.
From the circuit, diode is reverse biased. \[ I = I_{\text{drift}} = 30\,\mu A \]

Step 2:
Voltage drop across resistor.
\[ V_R = IR = (30 \times 10^{-6})(20) = 6 \times 10^{-4}\,V = 0.0006\,V \]

Step 3:
Voltage across diode.
\[ V_D = 6.0 - 0.0006 = 5.9994 = 5.99\,V \]
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