Step 1: Understanding the Concept:
In any aqueous solution at \(298\) K the ionic product of water is fixed: \(K_w = [\text{H}^+][\text{OH}^-] = 1\times10^{-14}\).
Step 2: Calculate:
\[ [\text{H}^+] = \frac{10^{-14}}{0.08} = 1.25\times10^{-13}\ \text{mol/L} \]
This equals \(0.125\times10^{-12}\) mol/L.
Step 3: Why the other options are wrong:
\(0.125\) mol/L and \(0.0125\) mol/L are far too big, since a basic solution has \([\text{H}^+] < 10^{-7}\). The value \(0.125\times10^{-10}\) comes from using \(10^{-12}\) in place of \(10^{-14}\).
Final Answer:
\([\text{H}^+] = 0.125\times10^{-12}\) mol/L, which is option (B).
\[ \boxed{0.125\times10^{-12}\ \text{mol/L}} \]