Step 1: Understanding the Concept
Molar conductivity is \(\Lambda_m=\dfrac{\kappa\times 1000}{M}\), where \(\kappa\) is conductivity and \(M\) is molarity.
Step 2: Find the unit
\(\kappa\) is in \(\text{ohm}^{-1}\text{ cm}^{-1}\) and concentration in \(\text{mol cm}^{-3}\).
Unit of \(\Lambda_m=\dfrac{\text{ohm}^{-1}\text{ cm}^{-1}}{\text{mol cm}^{-3}}=\text{ohm}^{-1}\text{ cm}^{2}\text{ mol}^{-1}\)
Step 3: Compare the options
The SI unit is \(\text{S m}^2\text{ mol}^{-1}\), while the common unit is \(\text{ohm}^{-1}\text{ cm}^2\text{ mol}^{-1}\), the second option.
Final Answer:
The common unit of molar conductivity is ohm inverse centimetre squared per mole.
\[ \boxed{\text{(B) }\text{ohm}^{-1}\text{ cm}^{2}\text{ mol}^{-1}} \]