Step 1: Write the formula
Chlorous acid is \(HClO_2\). Hydrogen is \(+1\) and oxygen is \(-2\).
Step 2: Solve
Let the oxidation state of chlorine be \(x\). Sum of oxidation numbers is zero:
\[ (+1) + x + 2(-2) = 0 \]
\[ x = +3 \]
Step 3: Check the options
\(+2\) is not found in chlorine oxoacids. \(+4\) is in \(ClO_2\). \(+7\) is in perchloric acid \(HClO_4\), where \(1 + x - 8 = 0\).
Final Answer:
Chlorine has oxidation state +3 in chlorous acid.
\[ \boxed{\text{(C)}\ +3} \]