Question:

What happens to the inductive reactance and the current in a purely inductive circuit if the frequency is halved?

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\(X_L = 2\pi f L\) is proportional to f, and the current in a purely inductive circuit is \(V/X_L\).
Updated On: Nov 4, 2026
  • Both, inducting reactance and current will be doubled.
  • Inductive reactance will be doubled and current will be halved.
  • Both, inductive reactance and current will be halved.
  • Inductive reactance will be halved and current will be doubled.
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The Correct Option is D

Solution and Explanation

Inductive reactance: \(X_L = 2\pi f L\), so \(X_L \propto f\). When f becomes \(f/2\), \(X_L\) becomes \(X_L/2\), i.e. it is halved.
The rms current in a purely inductive circuit is \(I = \frac{V}{X_L}\). With V unchanged and \(X_L\) halved, I is doubled.
Answer: (4) Inductive reactance will be halved and current will be doubled.
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