\[ xyz = \text{constant} \]
The potential due to a long charged wire is proportional to the logarithm of the distance from the wire. To find the equipotential surface, we sum the potentials from the three wires.
Step 1: For each wire, the potential depends on the perpendicular distance from the wire.
Step 2: The equipotential surface is where the total potential from the three wires is constant.
Step 3: After analyzing the expressions, we conclude that the correct relation is \( xy + yz + zx = constant} \), which satisfies the condition for an equipotential surface.
Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 
Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 