Question:
What are the reactants involved in Friedal Crafts alkylation?
What are the reactants involved in Friedal Crafts alkylation?
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Alkylation needs an alkyl halide with anhydrous AlCl3; acylation needs an acyl chloride.
Updated On: Oct 1, 2026
- \(\text{C}_6\text{H}_6+\text{NH}_3\)
- \(\text{C}_6\text{H}_6+\text{CH}_3\text{Cl}\)
- \(\text{C}_6\text{H}_6+\text{CH}_3\text{COCl}\)
- \(\text{C}_6\text{H}_6+\text{CH}_4\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Friedel-Crafts alkylation puts an alkyl group on a benzene ring using an alkyl halide and a Lewis acid, anhydrous \(\text{AlCl}_3\).
Step 2: Detailed Explanation
\[ \text{C}_6\text{H}_6 + \text{CH}_3\text{Cl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{CH}_3 + \text{HCl} \]
(A) with \(\text{NH}_3\) gives no such reaction. (C) with \(\text{CH}_3\text{COCl}\) is the acylation reaction, giving acetophenone. (D) methane is not an alkylating agent here.
Final Answer:
The alkylation reactants are benzene and methyl chloride, option (B). \[ \boxed{\text{C}_6\text{H}_6 + \text{CH}_3\text{Cl}} \]
Friedel-Crafts alkylation puts an alkyl group on a benzene ring using an alkyl halide and a Lewis acid, anhydrous \(\text{AlCl}_3\).
Step 2: Detailed Explanation
\[ \text{C}_6\text{H}_6 + \text{CH}_3\text{Cl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{CH}_3 + \text{HCl} \]
(A) with \(\text{NH}_3\) gives no such reaction. (C) with \(\text{CH}_3\text{COCl}\) is the acylation reaction, giving acetophenone. (D) methane is not an alkylating agent here.
Final Answer:
The alkylation reactants are benzene and methyl chloride, option (B). \[ \boxed{\text{C}_6\text{H}_6 + \text{CH}_3\text{Cl}} \]
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