Question:
Volume of 4.4 g CO$_2$ at STP is:
Volume of 4.4 g CO$_2$ at STP is:
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Just use: volume = (mass / molar mass) × 22.4
Updated On: Jun 10, 2026
- 22.4 L
- 2.24 L
- 11.2 L
- 44.8 L
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The Correct Option is B
Solution and Explanation
Concept:
At STP, 1 mole gas occupies 22.4 L.
Step 1: Moles of CO$_2$ \[ M = 44 \, g/mol \] \[ n = \frac{4.4}{44} = 0.1 \]
Step 2: Volume \[ V = n \times 22.4 = 0.1 \times 22.4 = 2.24 L \] Thus answer is 2.24 L.
Step 1: Moles of CO$_2$ \[ M = 44 \, g/mol \] \[ n = \frac{4.4}{44} = 0.1 \]
Step 2: Volume \[ V = n \times 22.4 = 0.1 \times 22.4 = 2.24 L \] Thus answer is 2.24 L.
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