Two thin lenses have a combined power of +9D. When they are separated by a distance of 20 cm, then their equivalent power becomes +27/5 D. Their individual power (in dioptre) is
Let P1 and P2 are the power of lenses.
Peq = P1 + P2
Given, Peq = 9
P1 + P2 = 9 ………………(1)
Power of lenses when distance is separated by d = 0.2 m ,
P'eq = P1 + P2 − dP1P2
Given, P'eq =\(\frac {27}{5}\)
\(\frac {27}{5}\) = 9 − 0.2 P1P2
on solving P1P2=18
P2 = \(\frac {18}{P_1}\)
From eq (1)
P1 + \(\frac {18}{P_1}\) = 9 …………(2)
P12 + 18 = 9 P1
P12 − 9P1+18=0
on solving P1 = 6 D
Now from eq (1)
6 + P2 = 9
P2 = 9 - 6
P2 = 3 D
Therefore the correct option is (A) 3,6
To a bird in air, a fish in water appears to be at 30 cm from the surface. If refractive index of water with respect to air is \(\frac {4}{3}\) ,the real distance of bird from the surface is
Lenses that are made by combining two spherical transparent surfaces are called spherical lenses. In general, there are two kinds of spherical lenses. Lenses that are made by joining two spherical surfaces that bulge outward are convex lenses, whereas lenses that are made by joining two spherical surfaces that curve inward are concave lenses.