Question:

Two sources give an interference pattern observed on a screen distance D away. The fringe width is 2W. If D is doubled, the fringe width will:

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Fringe width is directly proportional to screen distance D.
Updated On: Apr 16, 2026
  • become W/2
  • remains the same
  • become W
  • become 4W
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The Correct Option is D

Solution and Explanation


Step 1:
Fringe width $β = \fracλ Dd$.

Step 2:
If D is doubled, $β$ becomes $2β = 4W$ (since original $β = 2W$).
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