Question:

Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of 1:2. The ratio of self-inductance of two solenoids is

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Self-inductance is proportional to N²/l.
Updated On: Mar 18, 2026
  • 1:1
  • 1:2
  • 2:1
  • 1:4
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The Correct Option is C

Solution and Explanation


Step 1:
Self-inductance of a solenoid: L=₀(N²A)/(l)
Step 2:
Given N₁:N₂=1:2 and l₁:l₂=1:2.
Step 3:
(L₁)/(L₂)=((1)²/1)/((2)²/2)=(1)/(2) L₂:L₁=2:1
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