Question:
Two pendulums have time periods T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?
Two pendulums have time periods T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?
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Two pendulums have time periods T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?
Updated On: Apr 15, 2026
- $45^{\circ}$
- $90^{\circ}$
- $60^{\circ}$
- $30^{\circ}$
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The Correct Option is B
Solution and Explanation
Step 1: Analysis
The bigger pendulum takes $5T/4$ to complete one vibration.
Step 2: Comparison
In this time, the smaller pendulum completes $1.25$ vibrations.
Step 3: Phase Difference
The lead is $T/4$ seconds, which corresponds to $\frac{\pi}{2}$ radians or $90^{\circ}$.
Final Answer: (B)
The bigger pendulum takes $5T/4$ to complete one vibration.
Step 2: Comparison
In this time, the smaller pendulum completes $1.25$ vibrations.
Step 3: Phase Difference
The lead is $T/4$ seconds, which corresponds to $\frac{\pi}{2}$ radians or $90^{\circ}$.
Final Answer: (B)
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