Question:
Two particles of masses \(m\) and \(2m\) kept 1 m apart are attracted to each other by gravitational force. The acceleration of their centre of mass is \((G = \text{gravitational constant})\)}
Two particles of masses \(m\) and \(2m\) kept 1 m apart are attracted to each other by gravitational force. The acceleration of their centre of mass is \((G = \text{gravitational constant})\)}
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The centre of mass moves only due to external force. Internal forces cannot change the motion of the centre of mass.
Updated On: Apr 24, 2026
- \(Gm\)
- \(2Gm\)
- \(3Gm\)
- \(Gm^2\)
- zero
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The Correct Option is
Solution and Explanation
The two particles attract each other with equal and opposite internal gravitational forces.
Since there is no external force acting on the system:
\[
F_{\text{external}}=0
\]
The acceleration of the centre of mass is:
\[
a_{\text{CM}}=\frac{F_{\text{external}}}{m_1+m_2}
\]
So,
\[
a_{\text{CM}}=0
\]
Hence, the correct answer is: \[ \boxed{(E)\ \text{zero}} \]
Hence, the correct answer is: \[ \boxed{(E)\ \text{zero}} \]
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