Question:

Two parallel conductors A and B of equal length carry currents i and 10 i, respectively, in the same direction. Then

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Two current-carrying conductors attract each other if the currents flow in the same direction, and the force is the same for both.
Updated On: Apr 22, 2026
  • A and B will repel each other with the same force
  • A and B will attract each other with the same force
  • A will attract B, but B will repel A
  • A and B will attract each other with different forces
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the force between parallel current-carrying conductors.
The force per unit length between two parallel conductors carrying currents is given by Ampère's law: \[ F/L = \frac{\mu_0 i_1 i_2}{2\pi r} \] where \(i_1\) and \(i_2\) are the currents, \(r\) is the distance between the conductors, and \(\mu_0\) is the permeability of free space.

Step 2: Analyzing the situation.

- The currents in the conductors are in the same direction, so they will attract each other. The force is directly proportional to the product of the currents. Since the currents are different (i and 10i), the force depends on the magnitude of the currents. However, the force between the two conductors will be equal in magnitude for both.
- The forces are equal in magnitude and opposite in direction on each conductor.

Step 3: Conclusion.

The correct answer is (2) because the forces will be equal in magnitude and will result in attraction between the conductors.
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