Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in the figure. If the mass A starts moving away from mass B with acceleration 'a', then the acceleration of mass B will be :
Show Hint
- \(\frac{MF}{F + Ma}\)
- \(\frac{F + Ma}{M}\)
- \(\frac{Ma - F}{M}\)
- \(\frac{F - Ma}{M}\)
The Correct Option is D
Solution and Explanation
The only horizontal force on A is the spring force, so spring force \(= Ma\) (directed towards B).
On B, the spring exerts an equal and opposite force \(Ma\) opposing F.
Newton's second law for B: \(F - Ma = M a_B\), so \(a_B = \frac{F - Ma}{M}\).
Answer: (4) \(\frac{F - Ma}{M}\)
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