To find the ratio of the masses \(\frac{m_2}{m_1}\), we start by analyzing the forces acting on each block. Consider two blocks of masses \(m_1\) and \(m_2\) connected by a light unstretchable string passing over a smooth pulley.
Hence, the correct ratio of the masses \(\frac{m_2}{m_1}\) is 9:7, which matches the given correct option.
Step 1: Equation for acceleration The acceleration of the system is given by:
\[ a_{\text{sys}} = \frac{(m_2 - m_1)}{m_1 + m_2} \cdot g. \]
Substitute \(a_{\text{sys}} = \frac{g}{8}\):
\[ \frac{(m_2 - m_1)}{m_1 + m_2} \cdot g = \frac{g}{8}. \]
Cancel \(g\) from both sides:
\[ \frac{m_2 - m_1}{m_1 + m_2} = \frac{1}{8}. \]
Step 2: Solve for \(\frac{m_2}{m_1}\) Rearrange the equation:
\[ 8(m_2 - m_1) = m_1 + m_2. \]
Simplify:
\[ 8m_2 - 8m_1 = m_1 + m_2. \]
Combine like terms:
\[ 8m_2 - m_2 = 8m_1 + m_1. \]
\[ 7m_2 = 9m_1. \]
Take the ratio:
\[ \frac{m_2}{m_1} = \frac{9}{7}. \]
Final Answer: \(\frac{m_2}{m_1} = 9 : 7\).
The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 \(\Omega\) is connected across these points is ______ J. 