Question:
Two identical isolated capacitors A and B are charged so that each has a charge of 4C. If a charge of \(-2C\) is added to A and \(+2C\) to B, then the ratio of respective potentials is
Two identical isolated capacitors A and B are charged so that each has a charge of 4C. If a charge of \(-2C\) is added to A and \(+2C\) to B, then the ratio of respective potentials is
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For identical capacitors, \(V \propto Q\).
Updated On: Apr 24, 2026
- \(1:1\)
- \(1:2\)
- \(2:1\)
- \(3:1\)
- \(1:3\)
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The Correct Option is
Solution and Explanation
Step 1: Understanding the Concept:
Capacitance is constant for identical capacitors. \(V = \frac{Q}{C}\).
Step 2: Detailed Explanation:
Initial charge on each = \(4C\).
After adding: \(Q_A = 4C + (-2C) = 2C\), \(Q_B = 4C + 2C = 6C\)
\(V_A = \frac{Q_A}{C} = \frac{2C}{C} = 2\) V, \(V_B = \frac{6C}{C} = 6\) V
Ratio \(V_A : V_B = 2:6 = 1:3\)
Step 3: Final Answer:
Ratio is \(1:3\).
Capacitance is constant for identical capacitors. \(V = \frac{Q}{C}\).
Step 2: Detailed Explanation:
Initial charge on each = \(4C\).
After adding: \(Q_A = 4C + (-2C) = 2C\), \(Q_B = 4C + 2C = 6C\)
\(V_A = \frac{Q_A}{C} = \frac{2C}{C} = 2\) V, \(V_B = \frac{6C}{C} = 6\) V
Ratio \(V_A : V_B = 2:6 = 1:3\)
Step 3: Final Answer:
Ratio is \(1:3\).
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