Question:

Two identical coherent sources placed on a diameter of a circle of radius \(R\) at separation \(x\) \((x \ll R)\) symmetrically about the centre of the circle. The sources emit identical wavelength \(\lambda\) each. The number of points on the circle with maximum intensity is \((x = 5\lambda)\)

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Count carefully: \(n = 0\) and \(n = \pm5\) each give 2 points (on the diameter axis), while \(|n| = 1,2,3,4\) each give 4 points (symmetric in all four quadrants).
Updated On: Apr 20, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Path difference at point \(P\) on the circle: \(\Delta x = x\cos\theta\). For maxima: \(\Delta x = n\lambda\).
Step 2: Detailed Explanation:
\(\cos\theta = n\lambda/x = n/5\). Condition: \(|\cos\theta| \leq 1\). So, \(n = 0, \pm1, \pm2, \pm3, \pm4, \pm5\). \(n = 5\): \(\theta = 0^\circ, 180^\circ\) → 2 points. \(n = -5\): same 2 points. For \(|n| = 1,2,3,4\): each gives 4 points → total = \(4 \times 4 = 16\). \(n = 0\): gives 2 points. Total points: \(2 + 16 + 2 = 20\).
Step 3: Final Answer:
Number of maxima on the circle \(= 20\).
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