Question:
Two dice are rolled. What is the probability of getting a total of \(9\)?
Two dice are rolled. What is the probability of getting a total of \(9\)?
Show Hint
Probability is calculated as
\[
\boxed{
P(E)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}
}
\]
For two dice, the total number of equally likely outcomes is \(36\).
Updated On: Jul 15, 2026
- \(\dfrac{1}{4}\)
- \(\dfrac{1}{6}\)
- \(\dfrac{1}{9}\)
- \(\dfrac{1}{12}\)
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The Correct Option is C
Solution and Explanation
Step 1: Find the total number of outcomes.
When two fair dice are rolled,
\[
\text{Total outcomes}=6\times6=36.
\]
Step 2: Find the favourable outcomes. A total of \(9\) is obtained for \[ (3,6),\ (4,5),\ (5,4),\ (6,3). \] Thus, \[ \text{Number of favourable outcomes}=4. \]
Step 3: Calculate the probability. \[ P(\text{sum}=9) = \frac{4}{36} = \frac{1}{9}. \]
Step 4: Final conclusion. \[ \boxed{\frac{1}{9}} \] Hence, the correct option is \(\boxed{(C)}\).
Step 2: Find the favourable outcomes. A total of \(9\) is obtained for \[ (3,6),\ (4,5),\ (5,4),\ (6,3). \] Thus, \[ \text{Number of favourable outcomes}=4. \]
Step 3: Calculate the probability. \[ P(\text{sum}=9) = \frac{4}{36} = \frac{1}{9}. \]
Step 4: Final conclusion. \[ \boxed{\frac{1}{9}} \] Hence, the correct option is \(\boxed{(C)}\).
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