Concept:
The standard slope-intercept form of a straight line is
\[
y = mx + c
\]
where:
• \(m\) represents the slope (gradient) of the line.
• \(c\) represents the \(y\)-intercept, i.e., the point where the line cuts the \(y\)-axis.
To find the values of \(m\) and \(c\), we first convert the given equation into slope-intercept form.
Step-by-Step Solution:
• The given equation of the line is
\[
3x-5y-6=0
\]
• Rearrange the equation to isolate \(y\):
\[
-5y=-3x+6
\]
• Divide the entire equation by \(-5\):
\[
y=\frac{-3x+6}{-5}
\]
\[
y=\frac{3}{5}x-\frac{6}{5}
\]
• Compare this equation with the standard form
\[
y=mx+c
\]
\[
m=\frac{3}{5}, \qquad c=-\frac{6}{5}
\]
• Therefore,
\[
(m,c)=\left(\frac{3}{5},-\frac{6}{5}\right)
\]
Hence, the correct answer is
\[
\boxed{\left(\frac{3}{5},-\frac{6}{5}\right)}
\]