Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)
Show Hint
- 30.2 MeV
- 32.4 MeV
- 23.6 MeV
- 25.8 MeV
The Correct Option is C
Solution and Explanation
Binding energy of the two deuterons \(= 2 \times 2 \times 1.1 = 4.4\) MeV.
Binding energy of helium \(= 4 \times 7.0 = 28.0\) MeV.
Energy released \(= 28.0 - 4.4 = 23.6\) MeV.
Answer: (3) 23.6 MeV
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