To determine the energy required to remove a neutron from $_{6}^{13}C$, we need to calculate the difference in binding energy between the isotopes $_{6}^{12}C$ and $_{6}^{13}C$. Here are the steps and calculations:
Therefore, the energy required to remove a neutron from $_{6}^{13}C$ is 4.95 MeV.
To remove a neutron from \( ^{13}_6C \), the nuclear reaction can be represented as:
\(^{13}_6C \rightarrow ^{12}_6C + \text{neutron}.\)
The mass defect \(\Delta m\) is given by:
\(\Delta m = \left(12.000000 + 1.008665\right) - 13.003354 = -0.00531 \, \text{u}.\)
The energy required for this process is calculated using:
\(E = \Delta m \times 931.5 \, \text{MeV/u}.\)
Substituting values:
\(E = 0.00531 \times 931.5 \approx 4.95 \, \text{MeV}.\)
The Correct answer is: 4.95 MeV
Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 