Question:

Two cylinders A and B fitted with pistons contain equal amount of an ideal diatomic gas at 303 K. The piston of cylinder A is free to move and that of cylinder B is held fixed. The same amount of heat is given to the gas in each cylinder. If the rise in temperature of the gas in cylinder B is 63 K then the rise in temperature of the gas in A is

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Average translational energy of a molecule is 3/2 kT; an electron accelerated through V gets eV.
Updated On: Oct 1, 2026
  • \(35\) K
  • \(40\) K
  • \(45\) K
  • \(50\) K
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Average translational kinetic energy of a gas molecule is \(E_1 = \frac32kT\), where \(k = \frac{R}{N}\). The electron gains \(E_2 = eV\).

Step 2: Equate:
\[ \frac32\cdot\frac{R}{N}T = eV \Rightarrow T = \frac{2eVN}{3R} \]
Here N is the Avogadro-type number of molecules per mole and R is the gas constant, so \(\frac RN\) is the Boltzmann constant.

Final Answer:
The temperature is \(\frac{2eVN}{3R}\), option (B). \[ \boxed{T = \frac{2eVN}{3R}} \]
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