Question:

Energy of a gas/litre is \(600\) joule, then what will be its pressure?

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Translational kinetic energy per unit volume equals \(\frac32P\).
Updated On: Oct 1, 2026
  • \(4\times 10^5\) N/m\(^2\)
  • \(10^5\) N/m\(^2\)
  • \(6\times 10^5\) N/m\(^2\)
  • \(3\times 10^5\) N/m\(^2\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
For an ideal gas, the total translational kinetic energy is \(E = \frac32PV\). So the energy per unit volume is \(\frac{E}{V} = \frac32P\).

Step 2: Calculate:
Energy per litre: \(600\) J in \(1\) L \(= 10^{-3}\) m\(^3\), so \(\frac{E}{V} = 6\times10^5\) J/m\(^3\).
\[ P = \frac23\times\frac{E}{V} = \frac23\times6\times10^5 = 4\times10^5\ \text{N/m}^2 \]

Step 3: Other options:
\(6\times10^5\) is the energy density, not the pressure. \(3\times10^5\) would come from using \(P = \frac{E}{2V}\).

Final Answer:
The pressure is \(4\times10^5\) N/m\(^2\), option (A). \[ \boxed{4\times10^5\ \text{N/m}^2} \]
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