Question:

Two coils P and Q are kept near each other. When current in coil Q increases at the rate 10 $A/s$, the emf in coil P is 12 mV. When current of 1.5 A flows through coil P, the magnetic flux linked with coil Q in mWb is

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Mutual inductance $M$ is the same whether you consider coil P affecting Q or Q affecting P.
Updated On: Jun 19, 2026
  • 0.9
  • 1.2
  • 1.5
  • 1.8
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The Correct Option is D

Solution and Explanation

Step 1: Formula
Induced EMF $e = M \frac{dI}{dt}$ and Flux $\phi = MI$.

Step 2: Analysis

First, find mutual inductance $M$:
$12 \times 10^{-3} = M \times 10 \implies M = 1.2 \times 10^{-3}$ H.

Step 3: Calculation

Now find flux in coil Q when current in P is 1.5 A:
$\phi = M \times I_p = (1.2 \times 10^{-3}) \times 1.5 = 1.8 \times 10^{-3}$ Wb.

Step 4: Conclusion

Hence, the magnetic flux is 1.8 mWb. Final Answer: (D)
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