Question:

Two coils have mutual inductance \(0.5\,\text{H}\). If the current in the primary coil changes at the rate of \(4\,\text{A s}^{-1}\), the induced emf in the secondary coil is

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For mutual induction: \[ \boxed{e=M\frac{dI}{dt}} \] Larger mutual inductance or faster current change produces greater induced emf.
Updated On: Jun 8, 2026
  • \(0.5\,\text{V}\)
  • \(1\,\text{V}\)
  • \(2\,\text{V}\)
  • \(4\,\text{V}\)
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The Correct Option is C

Solution and Explanation


Step 1:
Recall the formula for induced emf due to mutual inductance. \[ e=M\frac{dI}{dt} \] where \[ M=0.5\,\text{H} \] and \[ \frac{dI}{dt}=4\,\text{A s}^{-1} \]

Step 2:
Substitute the values. \[ e=0.5\times4 \] \[ e=2\,\text{V} \]

Step 3:
Choose the correct option. \[ \boxed{e=2\,\text{V}} \] Therefore, \[ \boxed{\text{(C)}} \] is the correct answer.
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