Question:
Two cells each of $2V$ and internal resistance $0.1\,\Omega$ are connected in parallel combination. This combination is equivalent to a single cell with emf and internal resistance of
Two cells each of $2V$ and internal resistance $0.1\,\Omega$ are connected in parallel combination. This combination is equivalent to a single cell with emf and internal resistance of
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Identical cells in parallel → same emf, resistance halves.
Updated On: Apr 24, 2026
- $1V$ and $0.05\,\Omega$
- $2V$ and $0.05\,\Omega$
- $2V$ and $0.1\,\Omega$
- $4V$ and $0.05\,\Omega$
- $4V$ and $0.1\,\Omega$
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The Correct Option is B
Solution and Explanation
Concept:
• In parallel: emf remains same
• Internal resistances combine like parallel resistors
Step 1: EMF
\[ E = 2V \]
Step 2: Internal resistance
\[ r = \frac{0.1}{2} = 0.05\,\Omega \] Final Conclusion:
Option (B)
• In parallel: emf remains same
• Internal resistances combine like parallel resistors
Step 1: EMF
\[ E = 2V \]
Step 2: Internal resistance
\[ r = \frac{0.1}{2} = 0.05\,\Omega \] Final Conclusion:
Option (B)
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