Question

Two capacitors of capacitance \(2\mu F\) and \(6\mu F\) are connected in series. A potential difference of 800 V is applied to the outer plates of the two capacitors system. The charge on each capacitor will be :

• A. 1200 C
• B. 6000 C
• C. \(6000 \mu C\)
• D. \(1200 \mu C\)

Hint:

In series combination, charge remains same on all capacitors.

Answer 1

The Correct Option is D

Concept: For series capacitors: \[ \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} \] Charge is same on each capacitor: \[ Q = C_{eq} V \]

Step 1: Equivalent capacitance.
\[ \frac{1}{C_{eq}} = \frac{1}{2} + \frac{1}{6} = \frac{4}{6} \Rightarrow C_{eq} = \frac{6}{4} = 1.5 \, \mu F \]

Step 2: Charge.
\[ Q = C_{eq} V = 1.5 \times 800 = 1200 \, \mu C \]