Question:
Two capacitors \(C_1\) and \(C_2\) are charged to \(120\ V\) and \(200\ V\) respectively. It is found that connecting them together the potential on each one can be made zero. Then
Two capacitors \(C_1\) and \(C_2\) are charged to \(120\ V\) and \(200\ V\) respectively. It is found that connecting them together the potential on each one can be made zero. Then
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For the common potential to become zero after joining, the net charge must be zero: connect opposite plates so the charges cancel.
Updated On: Nov 13, 2026
- \(5C_1=3C_2\)
- \(3C_1=5C_2\)
- \(3C_1+5C_2=0\)
- \(9C_1=4C_2\)
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The Correct Option is B
Solution and Explanation
Charges: \(q_1=120C_1\) and \(q_2=200C_2\).
Joining them (with opposite polarity plates connected) the common potential is \(V=\frac{q_1-q_2}{C_1+C_2}\).
For \(V=0\) the charges must cancel: \(120C_1=200C_2\Rightarrow 3C_1=5C_2\).
Answer: (2) \(3C_1=5C_2\)
Joining them (with opposite polarity plates connected) the common potential is \(V=\frac{q_1-q_2}{C_1+C_2}\).
For \(V=0\) the charges must cancel: \(120C_1=200C_2\Rightarrow 3C_1=5C_2\).
Answer: (2) \(3C_1=5C_2\)
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