Two capacitors \(C_1\) and \(C_2 = 2C_1\) are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and \(C_1\) holds charge Q. The switch is closed. At steady state, the charge on each capacitors will be
Show Hint
- Q, 2Q
- Q/3, 2Q/3
- 3Q/2, 3Q
- 2Q/3, 4Q/3
The Correct Option is B
Solution and Explanation
Charge redistributes with same voltage across both.
Step 2: Detailed Explanation:
\(\frac{Q_1}{Q_2} = \frac{C_1}{C_2} = \frac{1}{2}\)
Total charge = Q
\(Q_1 = \frac{Q}{1+2} = Q/3\)
\(Q_2 = 2Q/3\)
Step 3: Final Answer:
Charges are Q/3 and 2Q/3.
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