Question:
Two blocks \(A(2m)\) and \(B(m)\) are connected and suspended by a spring. Find accelerations just after cutting the string.
Two blocks \(A(2m)\) and \(B(m)\) are connected and suspended by a spring. Find accelerations just after cutting the string.
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Immediately after cut $\Rightarrow$ spring force same, motion changes.
Updated On: Apr 23, 2026
- \(g,\ g/2\)
- \(g/2,\ g\)
- \(g,\ g\)
- \(g/2,\ g/2\)
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The Correct Option is B
Solution and Explanation
Concept:
Initially system in equilibrium $\Rightarrow$ spring force balances total weight.
Step 1: Initial tension in spring
\[ T = (2m + m)g = 3mg \]
Step 2: Just after cutting string
Spring force unchanged instantly. For block \(A\): \[ F_{\text{net}} = 3mg - 2mg = mg \Rightarrow a_A = \frac{mg}{2m} = \frac{g}{2} \] For block \(B\): Only gravity acts: \[ a_B = g \] Conclusion: \[ \left(\frac{g}{2},\ g\right) \]
Step 1: Initial tension in spring
\[ T = (2m + m)g = 3mg \]
Step 2: Just after cutting string
Spring force unchanged instantly. For block \(A\): \[ F_{\text{net}} = 3mg - 2mg = mg \Rightarrow a_A = \frac{mg}{2m} = \frac{g}{2} \] For block \(B\): Only gravity acts: \[ a_B = g \] Conclusion: \[ \left(\frac{g}{2},\ g\right) \]
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