Question:

To a 4 L of 0.2 M solution of NaOH, 2 L of 0.5 M NaOH are added. The molarity of resulting solution is

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$M_1V_1 + M_2V_2 = M_3(V_1+V_2)$.
Updated On: Apr 8, 2026
  • 0.9 M
  • 0.3 M
  • 1.8 M
  • 0.18 M
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
$M_1V_1 + M_2V_2 = M_3(V_1+V_2)$.
Step 2: Detailed Explanation:
Total moles = $4 \times 0.2 + 2 \times 0.5 = 0.8 + 1.0 = 1.8$ mol. Total volume = $4 + 2 = 6$ L. Molarity = $\frac{1.8}{6} = 0.3$ M.
Step 3: Final Answer:
The molarity is 0.3 M.
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