Question

Three resistors \( 10 \, \Omega \), \( 20 \, \Omega \), and \( 30 \, \Omega \) are connected to form a triangle. Across \( 30 \, \Omega \) resistor a 3V battery is connected. The current through \( 30 \, \Omega \) resistor is

• A. \( 0.75 \, \text{A} \)
• B. \( 1 \, \text{A} \)
• C. \( 1.5 \, \text{A} \)
• D. \( 0.5 \, \text{A} \)

Hint:

To solve for the current in resistive circuits, use Ohm's law: \( I = \frac{V}{R} \).

Answer 1

The Correct Option is B

Using Ohm's law, we can calculate the equivalent resistance of the triangular circuit. With the battery providing 3V, the current through the \( 30 \, \Omega \) resistor is calculated to be 1A.

Step 2: Conclusion.
The current through the \( 30 \, \Omega \) resistor is \( 1 \, \text{A} \), corresponding to option (b).