Question:
Three point charges +q, +2q and +Q are placed at the vertices of an equilateral triangle. If the potential energy of the system of three charges is zero, the value of Q in terms of q is
Three point charges +q, +2q and +Q are placed at the vertices of an equilateral triangle. If the potential energy of the system of three charges is zero, the value of Q in terms of q is
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For an infinite sheet the field is sigma over 2 epsilon, independent of distance.
Updated On: Oct 1, 2026
- \(-\frac{q}{3}\)
- \(\frac{-2q}{3}\)
- \(\frac{q}{2}\)
- \(\frac{3q}{2}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
For a uniformly charged infinite plane sheet, Gauss's law gives \(E = \frac{\sigma}{2\varepsilon_0}\). The field does not depend on the distance from the sheet.
Step 2: Look at the graphs:
Graph (A) is a straight line rising from the origin, so E grows with d. Graph (B) is a straight line falling to zero, so E decreases with d. Graph (D) is a vertical line, which is not a function of d. Graph (C) is a horizontal straight line, a constant E at all d.
Step 3: Pick:
A constant field matches the horizontal line of graph (C).
Final Answer:
The correct graph is (C). \[ \boxed{\text{(C)}} \]
For a uniformly charged infinite plane sheet, Gauss's law gives \(E = \frac{\sigma}{2\varepsilon_0}\). The field does not depend on the distance from the sheet.
Step 2: Look at the graphs:
Graph (A) is a straight line rising from the origin, so E grows with d. Graph (B) is a straight line falling to zero, so E decreases with d. Graph (D) is a vertical line, which is not a function of d. Graph (C) is a horizontal straight line, a constant E at all d.
Step 3: Pick:
A constant field matches the horizontal line of graph (C).
Final Answer:
The correct graph is (C). \[ \boxed{\text{(C)}} \]
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