Question

Three capacitors $A,B,C$ with respective capacitance of $1\,\mu F$, $2\,\mu F$ and $3\,\mu F$ are connected as shown. For a given voltage source $V$ connected across them, the combination that can store the maximum energy is

• A.

  

• B.

  

• C.

  

• D.

  

• E.

  

Hint:

For maximum energy storage: - Maximize equivalent capacitance - Parallel connection gives highest capacitance

Answer 1

Answer: (E)

Concept: Energy stored in capacitors: \[ U = \frac{1}{2}C_{\text{eq}} V^2 \] For a given voltage $V$, maximum energy corresponds to maximum equivalent capacitance.

Step 1: Understand combinations.
- Parallel combination increases capacitance: \[ C_{\text{eq}} = C_1 + C_2 + C_3 \] - Series combination reduces capacitance.

Step 2: Compare all options.
Option (E) shows all capacitors in parallel.

Step 3: Find equivalent capacitance for (E).
\[ C_{\text{eq}} = 1 + 2 + 3 = 6\,\mu F \] This is maximum possible.