Question

Three blocks of masses \(2\ \mathrm{kg}\), \(3\ \mathrm{kg}\) and \(5\ \mathrm{kg}\) are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force \(\mathrm{F} = 10\ \mathrm{N}\), then tension \(\mathrm{T_1}\) is

• A. 1 N
• B. 5 N
• C. 8 N
• D. 10 N

Hint:

In connected systems, find total acceleration first, then analyze forces on sections.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
Total mass of the system determines acceleration, then tension is force on remaining blocks.
Step 2: Detailed Explanation:
Total mass \(M = 2 + 3 + 5 = 10\ \mathrm{kg}\)
Acceleration \(a = F/M = 10/10 = 1\ \mathrm{m/s^2}\)
Tension \(T_1\) pulls 3 kg and 5 kg blocks: \(T_1 = (3 + 5) \times a = 8 \times 1 = 8\ \mathrm{N}\)
Step 3: Final Answer:
Tension \(T_1\) is 8 N.