Question:
The work done in moving a point charge of \(10\mu\text{C}\) through a distance of \(3\) cm along the equatorial axis of an electric dipole is
The work done in moving a point charge of \(10\mu\text{C}\) through a distance of \(3\) cm along the equatorial axis of an electric dipole is
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For an ideal dipole, potential on the equatorial axis is always zero.
Updated On: Apr 29, 2026
- \(10\times10^{-5}\) J
- \(30\times10^{-5}\) J
- \(20\times10^{-5}\) J
- \(5\times10^{-6}\) J
- zero
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The Correct Option is
Solution and Explanation
Potential on the equatorial axis of an electric dipole is zero at every point.
Therefore, potential difference between any two points on the equatorial axis is:
\[
\Delta V=0
\]
Work done:
\[
W=q\Delta V=0
\]
Hence,
\[
\boxed{(E)\ \text{zero}}
\]
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