Question

The volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P. is

• A. 5.6 dm\(^3\)
• B. 7.46 dm\(^3\)
• C. 22.4 dm\(^3\)
• D. 11.2 dm\(^3\)

Hint:

For complete combustion of hydrocarbons, use the stoichiometric coefficients to determine the amount of oxygen required.

Answer 1

The Correct Option is A

Step 1: Understanding the reaction.
The combustion of methane is represented as: \[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \] This equation shows that for each mole of methane, 2 moles of oxygen are required.

Step 2: Calculation.
For 0.25 moles of methane, the required oxygen is: \[ 0.25 \times 2 = 0.5 \, \text{moles of oxygen} \] At S.T.P., 1 mole of gas occupies 22.4 dm\(^3\), so the volume of oxygen required is: \[ 0.5 \times 22.4 = 5.6 \, \text{dm}^3 \]
Step 3: Conclusion.
The correct answer is (A) 5.6 dm\(^3\).